商师《土力学与基础工程》第三版(赵明华)课后习题答案武汉理工大学出版社.pdf 29页

'《土力学与基础工程》第三版�赵明华�课后习题答案 22.2dser+drwd(1−n)swrwswS1=(2)=(3)s=dr1+e1+envm1v=1vv=ev=v+v=1+edse=d=svsvsvvpsswmw100%m=dv=dw=100%m=wm=wdssswswwsswmsm=m+m=d(1+w)swswms1=dvdsw=d1+evwd2wswd=ses=100%s=⇒rrsrvevmd(1+w)d(1+w)rdwr+drser+drswswswswrwswr=g=g=g===v1+e1+e1+e1+evenvwdvd(1−n)3vws=sn=100%n=⇒e=s=100%=rv1+e1−nvenv2.3v=1s33d=2.70=32.2%=1.91g/cm=1.0g/cmsw"2.506srr33v=1,d=2.70,w=32.2%,=1.91g/cm,=1.0g/cmssw2 d(1+w)2.70(1+0.322)1.0swe=−1=−1=0.871.9131v=e=0.87cmv32v=wd=0.322*2.70=0.87cmws33v=1+e=1+0.87=1.87cm4m=d=2.70*1.0=2.70gssw5m=wd=0.322*2.70*1.0=0.87gwsw6m=m+m=3.57gswwdv0.87sw7s=*100%=*100%=100%rev0.87v8""ds−12.7−1*103r=g=g==9.1kN/mw1+e1+0.8732.472cm129.5g121.5g2.7wesrrrr"r,satd3m129.53v=72cmm=129.5gm=121.5gd=2.7===1.799g/cmssv72mm−m129.5−121.5(1)ws*100%w=*100%==*100%=6.6%msm121.5s3 mm121.5ssds=⇒vs===45vv=v−vs=72−45=27vd2.7swsv27m129.5−121.52vwe===0.60v===8wv451swv83ws==*100%=29.6rv27v34r=g=1.799*10=18.0kN/mms+vvw121.5+2735r=g=*10=20.6kN/msatv72"ms−vsw121.5−4536r"=g=g=*1010.6Kn/mv72ms121.53r=g=g=*10=16.9kN/mddv72rrrr"satd2.52.6832.0%ers=100%d=2.68w=32.0%rsvmvvvs=w*100%=100%⇒v=vw=w*100%=ww=vw⇒m=vwrwvsvmmmwvsssmvsm=dv∴vwv=dvwd=⇒=dvsssswsswvssvwswvdvwvssQe===dw=2.68*0.32=0.86svvssds(1+w)2.68×1+0.323∴r=g=*10=19kN/mw1+e1+0.8632.61.77g/cm,9.8%2.670.4610.943eDr3=1.77g/cmw=9.8%d=2.67e=0.461e=0.943sminmaxds(1+w)w2.67∗(1+0.098)e=−1=−1=0.6561.774 e−e0.943−0.656maxD===0.595re−e0.943−0.461maxminQ0.67>D>0.33∴r32.7=1.66g/cm,d=2.69s40%w?3dsw2.69∗1=1.66g/cmd=2.69s=40%e=−1=−1=0.620dsr1.66dse0.40∗0.62rw==*100%=9.2%d2.69s32.8w=28.5%,r=19kN/m,d=2.68,s>220.50.50.250.20.075<0.075mm9.418.621037.513.5%12343mN=1410.075mm9.4%+18.6%+21.0%+37.5%=86.9%50%d(1+w)2.68∗(1+0.285)∗1sw2e=−1=−1=0.811.9wd0.285∗2.68ss==∗100%=94.3%re0.8134N=14101.6Eazf3x3(Gn+Ean)k==176+0×0.5/51.6=1.7>1.3sEat−Gt25 6-66-736-75=22.0kN/mk6-72cos(−)ka=2sin(+)sin(−)2coscos(+)[1+]cos(+)cos(−)2oocos(35−20)=oooo2ooosin(35+15)sin(35−15)2cos20cos(20+15)[1+oooo]cos(20+15)cos(20−15)=0.526=12=0.5×18×2×0.526=170.44kNEahka6m2(2)G=0.5×(0.8+2.98)×6×22=249.48kN11x0=[0.5×6×0.4×22+0.5×6×(2.98-0.8)×22××(2.98-0.8)+0.8]=1.05m249.483326 o2(2.98−0.8)Gx0+Eaxf249.48×1.05+170.424×sin35×[0.8+3]k=z==1.73toEazf170.424×cos35×2xo(Gn+Ean)=249.48×0.55+170.424×0.55×sin35=1.37ks=oEat−Gt170.424×cos3536-8b=3md=12m=18.5kN/moc=15kPa=20ppcr1/46-81o(d+c.cot)×(18.5×1.2+15×cot20)0=+d=+18.5×1.2=152.68kPaPcr0oo20cot+−2cot20+−18022d(d+c.cot+)=04+dP104cot+−2o3×(18.5×1.2+15×cot20+18.5×)=4+18.5×1.2=181.23kPaoo20cot20+−18026.9b=1.5md=2.0m3o=18.2kN/mc=30.0kPa=22p1/436.91=0o1.5×(18.2×2.0+30.0×cot22+18.2×)P1=4+18.2×2.0=322.61kPao4o22cot22+−1802227 o2o=22Nq=tan(45+)exp(tan)2o=2(o+22)exp(tano)tan45222=7.8Nc=16.9N=6.9Pu=1.2cNc+qNq+0.4dN=1.2×30.0×16.9+18.2×2.0×7.8+0.4×18.2×1.5×6.9=967.668kPaP=Pu3=322.6kPa3Nc=16.9Nq=7.8N=4.1ic=iq=i=1sc=1.02sq=1.375s=0.6=0=0gc=gq=g=bc=bq=b=1d2.0==1.333b1.5dc=1+0.4×arctan1.333=1.37oo2dq=1+2tan22(1−sin22)arctan1.333=1.29d=11Pc=cNcscdcicgcbc+qNqsqdqiqgqbq+bNsdigb2=30.0×16.9×1.2×1.37×1×1×1+18.2××2.0×1.375×1.29×1×1×7.8+0.5×18.2×1.5×4.1×1×1×1×0.628 =1370.69kPaP=Pu/3=456.9kPa29'